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🔥 removing usused functions #645
It seems these functions are not required any more. The code was added in commit 7e32457
to fix issue #171. There are still regression tests for #171, so when this commit passes the CI, the functions may be removed for good.
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68
src/json.hpp
68
src/json.hpp
@ -4240,74 +4240,6 @@ class basic_json
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with range checking
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@sa @ref value() for access by value with a default value
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@since version 1.0.0
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*/
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template<typename T, std::size_t n>
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reference operator[](T * (&key)[n])
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{
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return operator[](static_cast<const T>(key));
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}
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/*!
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@brief read-only access specified object element
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Returns a const reference to the element at with specified key @a key. No
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bounds checking is performed.
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@warning If the element with key @a key does not exist, the behavior is
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undefined.
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@note This function is required for compatibility reasons with Clang.
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@param[in] key key of the element to access
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@return const reference to the element at key @a key
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@throw type_error.305 if the JSON value is not an object; in that cases,
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using the [] operator with a key makes no sense.
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@complexity Logarithmic in the size of the container.
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@liveexample{The example below shows how object elements can be read using
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the `[]` operator.,operatorarray__key_type_const}
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@sa @ref at(const typename object_t::key_type&) for access by reference
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with range checking
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@sa @ref value() for access by value with a default value
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@since version 1.0.0
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*/
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template<typename T, std::size_t n>
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const_reference operator[](T * (&key)[n]) const
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{
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return operator[](static_cast<const T>(key));
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}
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/*!
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@brief access specified object element
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Returns a reference to the element at with specified key @a key.
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@note If @a key is not found in the object, then it is silently added to
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the object and filled with a `null` value to make `key` a valid reference.
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In case the value was `null` before, it is converted to an object.
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@param[in] key key of the element to access
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@return reference to the element at key @a key
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@throw type_error.305 if the JSON value is not an object or null; in that
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cases, using the [] operator with a key makes no sense.
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@complexity Logarithmic in the size of the container.
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@liveexample{The example below shows how object elements can be read and
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written using the `[]` operator.,operatorarray__key_type}
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@sa @ref at(const typename object_t::key_type&) for access by reference
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with range checking
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@sa @ref value() for access by value with a default value
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@since version 1.1.0
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*/
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template<typename T>
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