/*M/////////////////////////////////////////////////////////////////////////////////////// // // IMPORTANT: READ BEFORE DOWNLOADING, COPYING, INSTALLING OR USING. // // By downloading, copying, installing or using the software you agree to this license. // If you do not agree to this license, do not download, install, // copy or use the software. // // // License Agreement // For Open Source Computer Vision Library // // Copyright (C) 2000-2008, Intel Corporation, all rights reserved. // Copyright (C) 2008-2011, Willow Garage Inc., all rights reserved. // Third party copyrights are property of their respective owners. // // @Authors // Nghia Ho, nghiaho12@yahoo.com // // Redistribution and use in source and binary forms, with or without modification, // are permitted provided that the following conditions are met: // // * Redistribution's of source code must retain the above copyright notice, // this list of conditions and the following disclaimer. // // * Redistribution's in binary form must reproduce the above copyright notice, // this list of conditions and the following disclaimer in the documentation // and/or other materials provided with the distribution. // // * The name of OpenCV Foundation may not be used to endorse or promote products // derived from this software without specific prior written permission. // // This software is provided by the copyright holders and contributors "as is" and // any express or implied warranties, including, but not limited to, the implied // warranties of merchantability and fitness for a particular purpose are disclaimed. // In no event shall the OpenCV Foundation or contributors be liable for any direct, // indirect, incidental, special, exemplary, or consequential damages // (including, but not limited to, procurement of substitute goods or services; // loss of use, data, or profits; or business interruption) however caused // and on any theory of liability, whether in contract, strict liability, // or tort (including negligence or otherwise) arising in any way out of // the use of this software, even if advised of the possibility of such damage. // //M*/ #include "precomp.hpp" namespace cv { int rotatedRectangleIntersection( const RotatedRect& rect1, const RotatedRect& rect2, OutputArray intersectingRegion ) { const float samePointEps = 0.00001f; // used to test if two points are the same Point2f vec1[4], vec2[4]; Point2f pts1[4], pts2[4]; std::vector intersection; rect1.points(pts1); rect2.points(pts2); int ret = INTERSECT_FULL; // Specical case of rect1 == rect2 { bool same = true; for( int i = 0; i < 4; i++ ) { if( fabs(pts1[i].x - pts2[i].x) > samePointEps || (fabs(pts1[i].y - pts2[i].y) > samePointEps) ) { same = false; break; } } if(same) { intersection.resize(4); for( int i = 0; i < 4; i++ ) { intersection[i] = pts1[i]; } Mat(intersection).copyTo(intersectingRegion); return INTERSECT_FULL; } } // Line vector // A line from p1 to p2 is: p1 + (p2-p1)*t, t=[0,1] for( int i = 0; i < 4; i++ ) { vec1[i].x = pts1[(i+1)%4].x - pts1[i].x; vec1[i].y = pts1[(i+1)%4].y - pts1[i].y; vec2[i].x = pts2[(i+1)%4].x - pts2[i].x; vec2[i].y = pts2[(i+1)%4].y - pts2[i].y; } // Line test - test all line combos for intersection for( int i = 0; i < 4; i++ ) { for( int j = 0; j < 4; j++ ) { // Solve for 2x2 Ax=b float x21 = pts2[j].x - pts1[i].x; float y21 = pts2[j].y - pts1[i].y; float vx1 = vec1[i].x; float vy1 = vec1[i].y; float vx2 = vec2[j].x; float vy2 = vec2[j].y; float det = vx2*vy1 - vx1*vy2; float t1 = (vx2*y21 - vy2*x21) / det; float t2 = (vx1*y21 - vy1*x21) / det; // This takes care of parallel lines if( cvIsInf(t1) || cvIsInf(t2) || cvIsNaN(t1) || cvIsNaN(t2) ) { continue; } if( t1 >= 0.0f && t1 <= 1.0f && t2 >= 0.0f && t2 <= 1.0f ) { float xi = pts1[i].x + vec1[i].x*t1; float yi = pts1[i].y + vec1[i].y*t1; intersection.push_back(Point2f(xi,yi)); } } } if( !intersection.empty() ) { ret = INTERSECT_PARTIAL; } // Check for vertices from rect1 inside recct2 for( int i = 0; i < 4; i++ ) { // We do a sign test to see which side the point lies. // If the point all lie on the same sign for all 4 sides of the rect, // then there's an intersection int posSign = 0; int negSign = 0; float x = pts1[i].x; float y = pts1[i].y; for( int j = 0; j < 4; j++ ) { // line equation: Ax + By + C = 0 // see which side of the line this point is at float A = -vec2[j].y; float B = vec2[j].x; float C = -(A*pts2[j].x + B*pts2[j].y); float s = A*x+ B*y+ C; if( s >= 0 ) { posSign++; } else { negSign++; } } if( posSign == 4 || negSign == 4 ) { intersection.push_back(pts1[i]); } } // Reverse the check - check for vertices from rect2 inside recct1 for( int i = 0; i < 4; i++ ) { // We do a sign test to see which side the point lies. // If the point all lie on the same sign for all 4 sides of the rect, // then there's an intersection int posSign = 0; int negSign = 0; float x = pts2[i].x; float y = pts2[i].y; for( int j = 0; j < 4; j++ ) { // line equation: Ax + By + C = 0 // see which side of the line this point is at float A = -vec1[j].y; float B = vec1[j].x; float C = -(A*pts1[j].x + B*pts1[j].y); float s = A*x + B*y + C; if( s >= 0 ) { posSign++; } else { negSign++; } } if( posSign == 4 || negSign == 4 ) { intersection.push_back(pts2[i]); } } // Get rid of dupes for( int i = 0; i < (int)intersection.size()-1; i++ ) { for( size_t j = i+1; j < intersection.size(); j++ ) { float dx = intersection[i].x - intersection[j].x; float dy = intersection[i].y - intersection[j].y; double d2 = dx*dx + dy*dy; // can be a really small number, need double here if( d2 < samePointEps*samePointEps ) { // Found a dupe, remove it std::swap(intersection[j], intersection.back()); intersection.pop_back(); j--; // restart check } } } if( intersection.empty() ) { return INTERSECT_NONE ; } // If this check fails then it means we're getting dupes, increase samePointEps CV_Assert( intersection.size() <= 8 ); Mat(intersection).copyTo(intersectingRegion); return ret; } } // end namespace